# Solve? #3n^2-2n+1=-3n^2+9n+11#

##### 1 Answer

Feb 26, 2017

#### Explanation:

We have (I think I've got this right...)

Let's set the whole thing equal to 0:

I'll try first to factor it into a form of

#ac=6# #bd=-10# #ad+bc=-11#

I'll do it in a chart format:

(first crack - got lucky!)

And so our factoring is:

We can see these points of intersection in the graph:

graph{(y-(3x^2-2x+1))(y-(-3x^2+9x+11))=0 [-10, 10, -14.42, 20]}